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angular frequency

PhysicsPeriodic motionWavesCircular motion

Summary

Angular frequency (ω) is the rate at which the phase of an oscillation or rotation advances, in radians per second. One cycle is 2π radians, so ω = 2πf = 2π/T. The testable point is converting between ω (rad/s), f (Hz) and T (s).

Detail

Meaning: Angular frequency is how fast the phase angle of a repeating motion grows. One full cycle covers 2π radians, so ω is 2π times the frequency f (cycles per second). It equals the angular speed of an object in uniform circular motion, and simple harmonic motion can be pictured as the projection of that circular motion. For a mass on a spring, ω depends on the spring constant and the mass. For a small-angle pendulum, it depends on g and the length, not the mass.

Equation: ω = 2πf = 2π/T, where ω is angular frequency (rad/s), f is frequency (Hz = s⁻¹) and T is period (s). Spring: ω = √(k/m), with k the spring constant (N/m) and m the mass (kg). Pendulum: ω = √(g/L), with g in m/s² and L in m.

On the MCAT: A passage gives x = A cos(ωt), a wave y = A sin(kx − ωt), or an AC voltage V = V₀ sin(ωt). You read off ω, then find f or T. Another common question is a scaling one. If the mass on a spring is quadrupled, ω halves and T doubles.

Common confusion: Students treat ω as if it were f. A value of ω = 10 rad/s is about 1.6 Hz, not 10 Hz, because you must divide by 2π. Also, ω describes how fast the phase advances. It is not the speed of the oscillating object, and a mass on a spring does not rotate.

Sources

  • Physics (Giancoli)
  • Fundamentals of Physics (Halliday, Resnick, Walker)
  • Physics for Scientists and Engineers (Knight)

Written for the MCAT and checked before it was published. For study reference only. Spotted an error? Let us know.