Archimedes' principle
Summary
Archimedes' principle says the buoyant force on an object that is fully or partly submerged in a fluid equals the weight of the fluid it displaces. Most testable: the force depends on the fluid's density and the submerged volume, not on the object's own weight.
Detail
Meaning: Pressure in a fluid increases with depth, so the upward push on the bottom of a submerged object is larger than the downward push on its top. The net upward force is the buoyant force, and it equals the weight of the fluid the object displaces. A floating object has a buoyant force equal to its weight, so the fraction submerged equals ρobject/ρfluid.
Equation: Fbuoy = ρfluid Vsub g, where Fbuoy is buoyant force (N), ρfluid is fluid density (kg/m³), Vsub is displaced fluid volume, equal to the submerged volume (m³), and g is 9.8 m/s².
On the MCAT: A block floats in water, then is moved to a denser liquid; it floats higher because less volume must be submerged. Another setup weighs an object in air and in fluid: apparent weight = true weight − Fbuoy, which yields the object's volume or density.
Common confusion: Buoyant force depends on the fluid's density and the displaced volume, not on the object's weight. A steel ship floats because its hull displaces a large volume of water. A floating object has Fbuoy equal to its weight; a fully submerged sinking object has Fbuoy less than its weight.
Sources
- Physics (Giancoli)
- Fundamentals of Physics (Halliday, Resnick, Walker)
- College Physics (Serway and Vuille)
Written for the MCAT and checked before it was published. For study reference only. Spotted an error? Let us know.