NaOH
Summary
NaOH is sodium hydroxide, a strong base that dissociates fully into Na⁺ and OH⁻. In organic reactions, OH⁻ acts as a nucleophile (SN2, ester hydrolysis) or as a base (E2, deprotonating acids), and the substrate and conditions decide which role dominates.
Detail
Meaning: NaOH is ionic, and in water it supplies OH⁻ with Na⁺ as a spectator ion. OH⁻ is both a strong nucleophile and a strong base. As a nucleophile it attacks the carbonyl carbon of esters (saponification) and, with heating, amides. It can also displace a leaving group from an unhindered alkyl halide by SN2 to give an alcohol. As a base it removes a proton: it triggers E2 elimination of alkyl halides (favored by heat and by secondary or tertiary substrates), converts carboxylic acids and phenols to their salts, and forms enolates in aldol reactions.
Equation: RCOOR′ + OH⁻ → RCOO⁻ + R′OH. R and R′ are alkyl groups (no units); Na⁺ is a spectator and is left out.
On the MCAT: You may be asked to predict the product when NaOH meets an ester, alkyl halide or acid. Extraction is also common. Aqueous NaOH turns carboxylic acids and phenols into water-soluble sodium salts, so they move to the aqueous layer while neutral compounds stay in the organic layer. Adding strong acid later regenerates the neutral acid.
Common confusion: Students assume NaOH gives substitution. With tertiary halides, or with heat, elimination wins. Saponification is also not reversible in base, because the carboxylic acid formed is deprotonated to a carboxylate that does not react with the alcohol. Acid-catalyzed ester hydrolysis is an equilibrium.
Sources
- Organic Chemistry (Wade)
- Organic Chemistry (Klein)
- Organic Chemistry (McMurry)
Written for the MCAT and checked before it was published. For study reference only. Spotted an error? Let us know.