zero order
Summary
A reaction is zero order in a reactant when its rate does not depend on that reactant's concentration, so rate = k. The most testable points: [A] versus time is a straight line with slope −k, and k has units of M/s.
Detail
Meaning: A reaction is zero order in a reactant when changing that reactant's concentration leaves the rate unchanged. The rate law is rate = k[A]⁰ = k. This typically happens when something other than the reactant's concentration limits the rate, such as an enzyme or a catalyst surface that is already saturated. The reactant is still consumed, at a constant rate.
Equation: [A] = [A]₀ − kt, where [A] is the concentration at time t (mol/L), [A]₀ is the initial concentration (mol/L), k is the rate constant (mol L⁻¹ s⁻¹) and t is time (s). The half-life is t½ = [A]₀/2k (s).
On the MCAT: A table of initial rates shows the rate staying the same while [A] is doubled, so the reaction is zero order in A. Graphs also give it away. [A] versus time is a straight line with slope −k, and rate versus [A] is a flat horizontal line. Enzyme passages use it too: at high substrate concentration the rate approaches Vmax and the reaction is roughly zero order in substrate.
Common confusion: Zero order does not mean the rate or k is zero, or that the reaction has stopped. Order is found from experimental data, not from the balanced equation's coefficients. Half-life is not constant here, unlike in first-order reactions. It shrinks as the reaction proceeds because t½ is proportional to the remaining [A].
Sources
- Chemistry: The Central Science
- Chemistry (Zumdahl)
- General Chemistry (Petrucci)
Written for the MCAT and checked before it was published. For study reference only. Spotted an error? Let us know.